Question
Thu May 10, 2012 By: Shourya Mukherjee
 

A body projected vertically upwards crosses point A and B separated by 28m, with velocities one-third and one-fourth of the initial velocity respectively. What is the maximum height reached by it above the ground? Shourya

Expert Reply
Fri May 11, 2012
 
apply, to find initial velocity.
v2-u2=2gs
here we have taken v as initial velocity
v2/16=v2/9  -2x10x 28
v=48?5 m/s
now to find max ht:
v=o at max height
so 0=v-2 x 10 x h
h=576m by putting v=48?5 m/s
 
 
 
 
 
Distance = 576 m
Home Work Help