Question
Sat June 16, 2012 By: Priyanka Kumar

34.2 g of sugar cane (C12H22O11)and 36g of glucose are dissolved in 810g of water.calculate the VP of this solution at 302K if VP of water is 30.2mm of Hg.

Expert Reply
Wed July 04, 2012
X ((C12H22O11) =0.1 /10.3
X(C6H12O6 ) = 0.2 /10.3
X(H2O) = 10/10.3
P0 -P /P0 = X
so,30.2 - p /30.2 =.0194
p = 29.614
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