Question
Thu August 02, 2012 By:

2.5 moles of sulphuryl chloride were dissolved in water to produce sulphuric acid and hydrochloric acid. How many moles of KOH will be required to completely neutralize the solution?

Expert Reply
Thu August 02, 2012

SO2Cl2 + 2H2O  ------> H2SO4 + 2HCl

 

Moles of HCl produced from 2.5 moles of SO2Cl2 = 5

Moles of H2SO4 produced from 2.5 moles of SO2Cl2 = 2.5

 

H2SO4 + KOH -----> K2SO4 + 2H2O

 

HCl + KOH -----> KCl + H2O

 

5moles of H2SO4 needs KOH = 10

2.5 moles of HCl needs KOH = 2.5

 

So, total KOH required = 12.5 moles

 

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