Question
Sat August 04, 2012 By: Tejas Pandey

200 mL of decimolar H2SO4 is mixed with 200 ml of semimolar NaOH, find the total MV.

Expert Reply
Thu August 30, 2012

The formula use will be:  MH2SO4VH2SO4 + MNaOHVNaOH = MfinalVfinal

 The no. of moles of 0.1 M sulphuric acid or MH2SO4VH2SO4 = 0.1 M x 0.2 l = 0.02 moles

 The no. of moles of 0.5 M NaOH or MNaOHVNaOH = 0.5 M x 0.2 l = 0.1 moles

 So, the total no. of moles or one can say MfinalVfinal = 0.02 + 0.1 = 0.12 moles

 The final volume = 0.2 litres + 0.2 litres = 0.4 litres

 So, the molarity of mixture obtained after mixing = total no. of moles/total volume

           

                                                                         = 0.12/0.4

                                                                     

                                                                         = 0.3 M

 

 

Home Work Help