Question
Sun December 02, 2012 By:
 

1.diagonals of a parallelogram ABCD intersect at O. if angleBOC=90 degree and angleBDC=40 degree,then find angleOAB.

Expert Reply
Mon December 03, 2012
 
Angle AOB=180-AngleBOC=180-90=90
AngleDBA=AngleBDC=40
in triangleOAB
AngleOAB=180-(AngleAOB+AngleOBA)=180-(90+40)=50
 
therfor Angle OAB=50 degree
Home Work Help