Question
Fri August 19, 2011 By: Hritwik Mishra
 

150 cells are supplying maximum current to external resistance of 0.6 ohm.the e.m.f. of each cell is 2 volts and internal resistance is 0.1 ohm show the arrangement of cell connection and find the value of current applied

Expert Reply
Tue August 23, 2011
for maximum cyrrent, the emf should be maximum and hence the cells are connected in series.
Therefore, emf of the battery = 150 x 2 = 300 volts
total internal resistance of the batter = 150 x 0.1 = 15 ohm.
 Total resistance of the circuit = 15 + 0.6 = 15.6 ohm
Now, current = tot. emf / tot. resistance = 300 / 15.6 = 19.2 Ampere
Home Work Help