0.44g of a hyrocarbon on compete combustion with oxygen gave 0.88g of water. show that the results are in aggrement with law of conservation of mass.
CO2 produced = 0.88 g
We know, 44 g CO2 contains 12 g C
then 0.88 g CO2 will contain 0.88 x 12/44 = 0.24 g C
Also, 18 g water contains 2 g of H
then 1.8 g water will contain 1.8 x 2/18 = 0.2 g of H
Remember for burning, the O2 was in excess which can be ignored. Since the hydrocarbon contains only C and H, 0.44 g of C and H in the products.