Question
Thu March 20, 2014 By: Shreehari Wadawadagi
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Expert Reply
Fri March 21, 2014
 
(i) rightwards double arrow(ii)
 
Since A subset of B, there is no element in A which does not belong to B.
Thus, A - B = empty set
Hence, (i) rightwards double arrow(ii)
 
(ii) rightwards double arrow(ii)
A - B = empty setrightwards double arrowA subset ofB rightwards double arrowA U B = B
Hence, (ii) rightwards double arrow(iii)
 
(iii) rightwards double arrow(iv) rightwards double arrowA U B = B rightwards double arrowA intersectionB = A
Hence, (iii) rightwards double arrow(iv)
 
(iv) rightwards double arrow(i)
Since, A intersectionB = A rightwards double arrow A subset of B
Thus, (iv) rightwards double arrow(i)
Hence, (i) left right double arrow(ii) left right double arrow(iii) left right double arrow(iv)
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