Question
Wed December 19, 2012 By: Manisha Vadagave
 

watching from the top of building 40m high the angle of depression of a moving car increases from 30 angle to 45degree in some internal time find the distance covered by the car in that interval of time.

Expert Reply
Thu December 20, 2012
 
AB = building = 40 m
Required distance travelled by the car = CD
 
In triangle ABC,
tan 45 = AB/BC
1 = 40/y
y = 40
 
 
In triangle ABD,
tan 30 = AB/x+y
1/root3 = 40/40+x
x=40(root 3 - 1)
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