Question
Fri March 25, 2011 By: Merin M

urgent mam.you didn't answer this wen i 1st sent u.plz dont do like that.

Expert Reply
Thu March 24, 2011
 
Dear Student,
 
Here is the solution:

Let AM = x cm
In quadrilateral OBAC, OB = OC = 9 cm and AB = AC = 6 cm
Thus, OBAC is a kite. It is known that the diagonals of a kite are perpendicular to each other.
∴ OA ⊥ BC
In right angled ∆AMC,
AM2 + MC2 = AC2   [Pythagoras theorem]  
MC2 = (62 – x 2) cm2 

OM2 + MC2 = OC2  
(9 – x)2 + (62 – x 2) = 92 
81 + x 2 – 18x + 36 – x 2 = 81
18x = 36
⇒x = 2

Regards
Team Topperlearning
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