Question
Thu October 25, 2012 By:
 

the value of Kw of a neutral solution at a particular temperature is 1*10^-5.What is its pH and pOH? please reply soon.

Expert Reply
Thu October 25, 2012
Kw = [H+][OH-] = 1.0 x 10-5
 
It is very important to know that neutral pH changes with temperature. The key part to this problem is that the solution is neutral! In a neutral solution the pH and pOH are equal and therefor so are their concentrations.  
 So, the value of [H+] = [OH-]. Lets assume this value is x.
 
So, x2 = 1.0 x 10-5
 
x = ?(1.0 x 10-5)
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