Question
Thu April 07, 2011 By: Rohit Varshney
 

the tangent to y=a(x^2)+bx+7/2 at(1,2) is parallel to the normal at the point (-2,2) on the curve y=x^2+6x+10. Find the value of a and b.

Expert Reply
Thu April 07, 2011
Dear student
You asked the question:
The tangent to at (1,2) is parallel to the normal at the point (-2,2) on the curve . Find the value of a and b.
Sol.
To solve this we equate the slope of tangent and normal of the corresponding curves.
Consider
  
Hope it resolve your quarry.
Regards
Team Topper
Ask the Expert