Question
Thu May 03, 2012 By: Akankshya Sahu
 

The K.E. of a body increases by 300%. The momentum of the body would increase by what percentage?

Expert Reply
Fri May 04, 2012
E = (1/2)mv^2 = (1/2)m^2v^2/m
=> E = (1/2) P^2/m
300% increase in means E becomes 4E
=> P becomes 2P
=> increase in P = 2P - P = P
= 100% increase in P.
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