Question
Thu October 13, 2011 By:

The interior angles of a polygon are in A.P.if the smallest angle is 120 degree and the common difference is 5 degree,then the no. of sides in the polygon is?

Expert Reply
Thu October 13, 2011

Smallest angle=120degrees

Common difference=5

A P is 120, 125, 130,……..

The sum of interior angles of a polygon= (n-2)180

Hence Sum of n terms of an A P = (n-2)180

n/2 {2.120+(n-1)5} = 180(n-2)

5n2 -125n +720 = 0

n2 -25n +144=0

n=9 or 16

Hence number of sides can be 9 or 16

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