Question
Thu May 10, 2012 By: Shourya Mukherjee
 

The distance traveled by a body in the nth second is given by the expression (2+3n).Find the initial velocity & acceleration. Also, find the final velocity at the end of 2 seconds.

Expert Reply
Mon May 14, 2012
Distance travelled by an object in n th sec=u+a(2n-1)/2   this is formula
so,    2+3n=u+a(2n-1)/2
        2+3n=u+an-a/2
 
now equating both parts:
an=3n         2=u-a/2
a=3             u=7/2=3.5m/s
Ask the Expert