Question
Thu February 17, 2011 By: Sashank G

Resistance

Expert Reply
Fri February 18, 2011
Dear student
we know that, power =  ( Voltage)2 / resistance
In series, net resistance = 3R
Therefore (voltage)2 = power x resistance = (X) (3R) = 3XR
In parallel, net resistance = R/3
Therefore, power dissipated =  ( Voltage)2 / resistance = (3XR) / (R/3) = 9X
Hope this helps.
Regards
Team
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