﻿
Question
Sun March 18, 2012 By:

# Q1 HOW WOULD LIGHT GET REFRACTED THROUGH A TRANSPARENT PRISM?

Sun March 18, 2012

Consider a triangular glass prism. It has two triangular bases and three rectangular lateral surfaces. These surfaces are inclined to each other. The angle between its two lateral faces is called the angle of the prism. Below is  an activity to study the refraction of light through a triangular glassprism.

Activity 1
• Fix a sheet of white paper on a drawing board using drawing pins.
• Place a glass prism on it in such a way that it rests on its triangular base. Trace the outline of the prism using a pencil.
• Draw a straight line PE inclined to one of the refracting surfaces, say AB, of the prism.
• Fix two pins, say at points P and Q, on the line PE as shown
• Look for the images of the pins, fixed at P and Q, through the other face AC.
• Fix two more pins, at points R and S, such that the pins at R and S and the images of the pins at P and Q lie on the same straight line.
• Remove the pins and the glass prism.
• The line PE meets the boundary of the prism at point E (see Fig. 4). Similarly, join and produce the points R and S. Let these lines meet the boundary of the prism at E and F, respectively. Join E and F.
• Draw perpendiculars to the refracting surfaces AB and AC of the prism at points E and F, respectively.
• Mark the angle of incidence (<i) the angle of refraction (<r) and the angle of emergence (<e) as shown

Refraction of light through a triangular glass prism

Here PE is the incident ray, EF is the refracted ray and FS is the emergent ray. You may note that a ray of light is entering from air to glass at the first surface AB. The light ray on refraction has bent towards the normal. At the second surface AC, the light ray has entered from glass to air. Hence it has bent away from normal. Compare the angle of incidence and the angle of refraction at each refracting surface of the prism. Is this similar to the kind of bending that occurs in a glass slab? The peculiar shape of the prism makes the emergent ray bend at an angle to the direction of the incident ray. This angle is called the angle of deviation. In this case <D is the angle of deviation. Mark the angle of deviation in the above activity and measure it.

Related Questions
Wed February 15, 2017

# in an experiment the focal length of a convex lens a student obtained a sharp and inverted image of a distant tree on the screen behind the lens.she then removed the screen and looked through lens in the direction of the object .she will see a) an inverted image of the tree at the focus of the lens b)no image as the screen is removed c) a blurered image on the wall of laboratory d0 an erect image of the tree on the lens pls explain me the answer elaborately

Sun January 29, 2017

﻿