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Question
Mon March 14, 2011

# Property of a A.P.

Mon March 14, 2011
Dear student,

Since pth term of an AP is q and qth term is p

Therefore, a + (p â 1)d = q                    (i)

and a + (q â 1)d = p                             (ii)

Subtracting equation (ii) from equation (i), we get,

(p â 1)d â (q â 1)d = q â p

d = -1
Substituting the value of d in (1), we get
a = p + q - 1

Now, (p+q)th term will be given by

a + (p+q-1)d = p + q - 1 + (p + q - 1)(-1) = 0

We hope that clarifies your query.

Regards,

Team

TopperLearning

Since pth term of an AP is q and qth term is p
Therefore, a + (p â 1)d = q                    (i)
and a + (q â 1)d = p                             (ii)
Subtracting equation (ii) from equation (i), we get,
(p â 1)d â (q â 1)d = q â p

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