Question
Sun March 18, 2012 By:

Please integrate the following....

Expert Reply
Tue March 27, 2012
The given expression can be written as
 
1/b2{ (1 - a2)/(a+bx)2 - 2abx/(a+bx)2 }
 
the first expression integrates to (a2 - 1)/b(a+bx)
and the other expression can be integrated by substituting 2abx = A(derivative of denominator) + B and then finding the values of A and B
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