Question
Sun March 18, 2012 By:

PLEASE ANSWER THIS QUESTION: find the integration of: [(x2+2)(x2+1)]/[(x2+3)(x2+4)]

Expert Reply
Sun March 18, 2012
Put x2 = y
The function reduces to: (y+1)(y+2) / (y+3)(y+4)
Add and subtract 1,
Function = 1 + [(y+1)(y+2) - (y+3)(y+4)/ (y+3)(y+4)]
By partial fractions, we get,
Function = 1 + 2/y+3 - 6/y+4 = 1 + 2/x2+3 - 6/x2+4
 
Now, this function can easily be integrated.
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