Question
Mon August 27, 2012 By:

integrate e^2x-1/e^2x+1 dx

Expert Reply
Tue August 28, 2012
Multiply the given function by e^(-x), we get,
 
(e^2x - 1) / (e^2x + 1) =
(e^x-e^-x)/(e^x+e^-x)
 
Integral (e^x-e^-x)/(e^x+e^-x) dx =
Integral 1/(e^x+e^-x) d(e^x+e^-x) =
log(e^x+e^-x)+C
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