Question
Sat June 30, 2012 By:
 

In how many ways can three persons, each throwing a single dice once, make sum of 15?

Expert Reply
Sun July 01, 2012
Answer : Given :there are 3 persons, each throwing a single dice once, make sum of 15
to find : probability of above said event
 
Let E be the event which says that there are  three persons,
each throwing a single dice once, make sum of 15
 
As there are 3 dices been thrown , therefore the total number of events would be =63 { here six is the the numbers coming in a single dice }
= 216
 the E would contain samples = { ( 3 ,6,6 ) , ( 6,3,6) , ( 6,6,3) , (4,5,6) (4,6,5) ,(5,4,6) ,(5,6,4) , (6,4,5) (6,5,4 ) , (5,5,5 ) , (1,5,6) ,(1,6,5) ,(5,1,6) ,(5,6,1) ,(6,1,5) ,(6,5,1) ,(2,4,6 ),(2,6,4) ,(4,2,6),(4,6,2) ,(6,2,4) ,(6,4,2) ,(3,3,6) ,(3,6,3) ,(6,3,3) }
 
n(E) =25
 
Probability = no. of favourable event (E) / total no. of events
                 = 25 / 216 answer

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