Question
Thu September 29, 2011 By:
 

In an experiment , 2 moles of HI are taken into an evacuated 10 litre container at 720K(temperature). The equilibriun constant equals to 0.0156 for the gaseous reaction . 2HI(g)= H2(g)+I2(g). calculate the amount of HI,H2,I2, at equilibrium.

Expert Reply
Fri September 30, 2011

Let at equilibrium, [H2] = [I2] = x

                               2HI (g) H2 (g) + I2 (g)

Initial conc.            2/10 M                   0           0

At equilibrium        0.2 -2x                   x            x  

 

                            0.125 = x / (0.2-2x)

                             x = 0.025-0.25x

                             x = 0.025 /1.25   

                             x=0.02

     Therefore, the equilibrium conc. of H2, I2 and HI are

                    [H2] =0.02M

                   [I2] =0.02M

                   [HI] =0.2-0.02 =0.18M

                  

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