Question
Sun February 05, 2012 By:
 

how to solve: Log [H+]=-9.7

Expert Reply
Mon February 06, 2012
Given,  Log [H+]=-9.7
By taking antilogarithm on both side of the above equation,
Antilog (log [H+])=Antilog (-9.7)
[H+] = Antilog ( -9 - 0.7 + 1 - 1)  [Adding and subtracting 1 on the RHS side]
[H+] = Antilog ( -10 + 0.3)
[H+] = 1.995 x 10-10
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