Question
Wed June 15, 2011 By: Vinayakasai Vasudev
 

how many atoms of each type are present in 143 grams of washing soda

Expert Reply
Fri June 17, 2011
Gram molecular mass of Na2CO3 = 106 g
so 106g of Na2CO3 = 1mol
  143g of Na2CO3 = 143 / 106 = 1.35 mol
 
Now, 1 mol of Na2CO3 contains = 2 x 6.022 x 1023 atoms of sodium
so   1.35 mol of Na2CO3 contains = 1.35 x 2 x 6.022 x 1023
                                               = 16.25 x 1023 Na atoms
 
1 mol of Na2CO3 contains = 6.022 x 1023 atoms of carbon
1.35 mol would have = 1.35 x 6.022 x 1023
                              = 8.13 x 1023 carbon atoms
 
1 mol of Na2CO3 contains = 3 x 6.022 x 1023 atoms of oxygen
1.35 mol would have = 1.35 x 3 x 6.022 x 1023
                              = 24.39 x 1023 oxygen atoms
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