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Question
Tue December 18, 2012

# from a pt 50m away fro the base of multistored bilding the angle of elevation of the 1st floor is found to be 30 degree & the angle of elevation of 15th floor is found to be 60 degree what is the distance between 1st floor & the 15th floor

Thu December 20, 2012

AB - multistoryed building
C - first floor
A - 15th floor

Required distance = AC

In triangle BOC,
tan 30 = BC/OB
1/root 3 = BC/ 50
BC = 50 / root3

In triangle AOB,
tan 60 = AB/OB
root 3 = (BC + AC) / 50

Now, in the above equation, put the value of BC to get the required distance AC.
Related Questions
Sun September 11, 2016

# The tallest tower in a city 100mt high and a multistoryed hotel at the city center is 20mt high. The angle of elevation of the top of the tower of the hotel is 3°36' . A building H meter high is situated on the road connecting the tower with city center at a distance of 1Km from the tower. Find the value of H .if the top of the hotel, top of the building and top of the tower in a straight line .Also find distance of the tower from the city center?

Tue February 23, 2016

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