for a natural number n. the number 8raiseto n can never end with the digit execpt zero
Let 8n ends with 0
=> 8n = 10a ( where a is any natural no)
8n = 2 x 5 x a
=> 8n has 2 and 5 as its prime factors . . . . . . .(1)
But fundamental theorem of arithmetic states that 8n can only have two as its prime factors [Since, 8n = (2 x 2 x 2)n ] . . . .(2)
Thus, from (1) and (2), it can be said that our supposition is wrong.
Hence 8n can never end with 0.