Let the outer square be ABCD, of 14cm each side.
Areas of this square=14x14= 196 Sq. CM .............. (i)
As there is a gap of 3 cm from each of the wall, hence it becomes another square (EFGH), each side of (14-3-3=) 8 cm.
Since there are semicircles within this EFGH, it makes another internal square (IJKL), each side of (8-2-2=) 4 cm.
Hence area within non-shaded portion = area of square IJKL of each side of 4 cm + 4 semicircle of dia 4 cm each
= 4x4 + 4x(3.14 x 2x2 /2)
= 16 + 25.12= 41.12 Sq Cm ....... (ii)
Hence area of shaded portion = (i) â (ii) = 196-41.12
Hence area of shaded portion= 154.88 Sq. Cm