Question
Sun June 10, 2012 By: Kanu Singh
 

Find the Angles of the triangle formed by vectore A= 2i-j+k, B= i-3j-5k and C= 3i-4j-4k? thank you

Expert Reply
Mon June 11, 2012
angle between A &B is 90 degree as, A.B=(2i-j+k).(i-3j-5k)=0=AB cos theta
SIMILARLY,angle between B &C is cos -1(?35/?41) degree asB.C=35=?35x?41 cos theta
SIMILARLY,angle between C &A is cos -1(?6/?35) degree asB.C=6=?35x?6 cos theta
Related Questions
Tue March 07, 2017

Q)

Ask the Expert