Question
Tue September 18, 2012 By:

Factorise : 64a^3 + 125y^3 - 64z^3 +240xyz

Expert Reply
Tue September 18, 2012

64x3 + 125y3 - 64z3 + 240xyz

= (4x)3 + (5y)3 + (-4z)3 - 3(4x)(5y)(-4z)

= [(4x) + (5y) + (-4z)] [(4x)2 + (5y)2 + (-4z)2 - (4x)(5y) - (5y)(-4z) - (4x)(-4z)]

= (4x + 5y - 4z) (16x2 + 25y2 + 16z2 - 20xy + 20yz + 16zx)

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