Question
Tue September 11, 2012 By:

Calculate the median of the data.

Expert Reply
Wed September 12, 2012

The gaps between mid values of the intervals are 10 each.

Now, 10/2 = 5.

For the mid value 115, lower class limit = 115 - 5 = 110

And upper limit = 115 + 5 = 120.

Hence, the given table can be reconstructed as

n = 384, n/2 = 192

Median class = 150 - 160,

Lower limit of the median class, l = 150

Frequency of the median class, f = 116

Cumulative frequency of the class interval preceding the median class, cf = 151

Width of each class interval, h = 10.

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