Question
Fri February 15, 2013 By: Padmakrith
 

A sequence is given by last term=n^2-1, where n belongs to N. Is this sequence an A.P?

Expert Reply
Fri February 15, 2013
An = n2 - 1
 
An-1 = (n-1)2 - 1 = n2 - 2n + 1 - 1 = n2 - 2n 
 
So, 
An - An-1 = n2 - 1 - n2 + 2n = 2n - 1 
 
Since this is not constant , hence it is not an AP
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