Question
Sun February 10, 2013 By: Renu Mariam John
 

A household circuit has a fuse of 5A rating.calculate the number of bulbs of rating 60w -220v each that can be connected in this circuit.

Expert Reply
Mon February 11, 2013
In house hold circuits, the loads are placed in parallel connection.
thus, current drawn by one bulb, i = P/V = 60/220 = 3/11 A
 
let total number of bulbs be N
Since in parallel connection, total current is sum of currents in all the branches,
thus Ni < 5
hence N (a maximum integer) can be determined.
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