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Question
Sun February 10, 2013

# A household circuit has a fuse of 5A rating.calculate the number of bulbs of rating 60w -220v each that can be connected in this circuit.

Mon February 11, 2013
In house hold circuits, the loads are placed in parallel connection.
thus, current drawn by one bulb, i = P/V = 60/220 = 3/11 A

let total number of bulbs be N
Since in parallel connection, total current is sum of currents in all the branches,
thus Ni < 5
hence N (a maximum integer) can be determined.
Related Questions
Wed January 18, 2017

# A cell of emf E and internal resistance r is connected to two external resistance R1 and R2 and a perfect ammeter.The current in the circuit is measured in four different situation: (i)without any external resistance in the circuit (ii)with resistance R1 only (iii)with Ri and R2 in series combination (iv)with R1 and R2 in parallel combination The currents measured in the four cases are 0.42A,1.05A,1.4A and 4.2A,but not necessarily in that order.Identify the currents corresponding to the four cases mentioned above.

Thu November 24, 2016

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