Question
Wed September 05, 2012 By:

A force of 4.0N acts on a body of mass 2.0kg for 4.0s. Assuming the body to be initially at rest,Find the distance covered in 10s after the force starts acting?

Expert Reply
Sat September 08, 2012
Acceleration acting on body for 4 sec. = 4/2 = 2m/ss
now distance covered in these 4 sec: s1 = 1/2(2)(4)2 = 16 m    (usin gthe second equation of motion)
now velocity after 4 sec = 2*4 = 8m/s   (using the first equation of  motion)
 
thus now the velocity will remain same = 8m/s
and the distance covered in remaining 6 sec = s2 = 6*8  = 48m
thus total distance = s1 + s2=  64m
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