A dirt is thrown horizontally with an initial speed of 10m/s toward point P, the bull's eye on a dirt board. It hits on point Q on the rim, vertically below P, 0.19s later. (a) What is the distance PQ? (b) How far away from the dirt board is the dart released?
y = y0 + v0y t ? 1/2 gt2 ? y = ? 1/2 gt2
y = ? 1/2 gt2 = ?1/2 (9.8 m/s2 )(0.19 s)2
The dart hits 17.7 cm below the bulls eye.