Question
Fri October 28, 2011 By:

A body of 2kg falls from rest.What will its kinetic energy during the fall at the end of 2S? (assume g=10m/s square)

Expert Reply
Sat October 29, 2011

K.E=1/2(mv2)

m=2kg

from ,v=u+at

u=0 m/s

t=2 sec

a=g=10 m/s2

v=0 +10 x2

v=20 m/s

K.E=1/2(mv2)

  =1/2 x2x20x 20

=400 J

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