Question
Tue March 08, 2011 By: Arunima Iyer

A ball is dropped on to the floor from a height of 10 m. It rebounds too a height of 2.5m.If the ball is in contact with the floor for 0.001s, what is the average accelarartion during contact?

Expert Reply
Tue March 08, 2011
v1 = root (2gh) = 14m/s

v2 = -7m/s.

Hence, average acceleration aaverage = v1 - (-v2)/0.02 = 21/0.02 = 1050m/s2
Ask the Expert