Question
Sun December 02, 2012 By:
 

4^(x+1)+4^(1-x)=10 solve and 2^2x-3.2^(x+2)+32=0

Expert Reply
Mon December 03, 2012
 
 
 
 
 
 

22 x – 3.2( x + 2) + 32 = 0

? 22 x – 3.2 x .22 + 32 = 0

? 22 x – 3.2 x .4 + 32 = 0

? 22 x – 12.2 x + 32 = 0

? 22 x – 8.2 x – 4.2 x + 32 = 0

? 2 x (2 x – 8) – 4 (2 x – 8) = 0

? (2 x – 4) (2 x – 8) = 0

? 2 x = 8 or 2 x = 4

? 2 x = 23 or 2 x = 22

? x = 3 or x = 2

Thus, the value of x is 3 or 2.

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